# Coulomb’s law for the magnitude of the force F between two particles with charges Q and Q separated by a distance d is | F |= K | QQ | d 2 , where K…

Coulomb’s law for the magnitude of the force F

between two particles with charges  Q

and  Q

separated by a distance d

is

|F|=K|QQ

|

d

2

,

where K=1

4πϵ

0

, and ϵ

0

=8.854×10

−12

C

2

/(N⋅m

2

)

is the permittivity of free space.

Consider two point charges located on the x axis: one charge, q

1

= -19.0 nC

, is located at x

1

= -1.745 m

; the second charge, q

2

= 36.0 nC

, is at the origin (x=0.0000)

What is the net force exerted by these two charges on a third charge q

3

= 52.5 nC

placed between q

1

and q

2

at x

3

= -1.060 m

?

Your answer may be positive or negative, depending on the direction of the force.

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