21. Determine the amount of heat given off or absorbed by each of processes. BELOW ARE THE ANSWERS BUT I NEED EXPLAINING. In problem “a” where did -201.2kj/mol gas and -237.6 jk/mol liquid come from? PLEASE HELP
a) evaporation of 0.80 g of CH3OH Reaction: 0.025 CH3OH(l) Æ 0.025 CH3OH(g)
q = (0.025 mols gas)(-201.2 kJ/mol gas) – (0.025 mols liquid )(-237.6 kJ/mol liquid) = 0.91 kJ absorbed
b) decomposition of 3.2 g of CaCO3(s) to CaO(s) and CO2(g) Reaction: 0.032 CaCO3(s) Æ 0.032CaO(s) + 0.032 CO2 (g)
q = (0.032 mol CaO)(-635.1) +(0.032 mol CO2)(-393.51 kJ/mol) – (0.032 mol CaO)(1206.9 kJ/mol) = 5.7 kJ absorbed
c) reaction of 4.0 g of H2(g) with excess N2(g) to produce NH3(g) 2.0 H2(g) + 0.67 N2 (g) Æ 1.3 NH3(g)
q = (1.3 mol NH3)(-46.11 kJ/mol) = – 61.48 kJ 61.48 kJ are released.
d) reaction of 12 g of NH3(g) with excess HCl(g) to produce NH4Cl(s) 0.71 NH3(g) + 0.71 HCl (g) Æ 0.71 NH4Cl(s) q = (0.71 mol){ -314.4 -(-46.11) – (-92.30)} kJ/mol= -1.2 x 102 kJ 120 kJ of heat are released.
Show more
Delivering a high-quality product at a reasonable price is not enough anymore.
That’s why we have developed 5 beneficial guarantees that will make your experience with our service enjoyable, easy, and safe.
You have to be 100% sure of the quality of your product to give a money-back guarantee. This describes us perfectly. Make sure that this guarantee is totally transparent.
Read moreEach paper is composed from scratch, according to your instructions. It is then checked by our plagiarism-detection software. There is no gap where plagiarism could squeeze in.
Read moreThanks to our free revisions, there is no way for you to be unsatisfied. We will work on your paper until you are completely happy with the result.
Read moreYour email is safe, as we store it according to international data protection rules. Your bank details are secure, as we use only reliable payment systems.
Read moreBy sending us your money, you buy the service we provide. Check out our terms and conditions if you prefer business talks to be laid out in official language.
Read more